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3(x^2+3x-118)=0
We multiply parentheses
3x^2+9x-354=0
a = 3; b = 9; c = -354;
Δ = b2-4ac
Δ = 92-4·3·(-354)
Δ = 4329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4329}=\sqrt{9*481}=\sqrt{9}*\sqrt{481}=3\sqrt{481}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-3\sqrt{481}}{2*3}=\frac{-9-3\sqrt{481}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+3\sqrt{481}}{2*3}=\frac{-9+3\sqrt{481}}{6} $
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